Quantum particle moving in potential V(x,y) = |x|^3 + |y|^3. Probability density and mean position.
#quantum #physicspic.twitter.com/lhseru7svS
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Another argument would be is that the Hamiltonian is C4v symmetric (symmetry of the square). The decomposition in terms of irreps may (or may not) be interesting as well?
So it’s expected that a potential with a triangular symmetry would have a wave function that is triangle-y?
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Yes indeed, you would be able to decompose the wave function into representations of the symmetry group, each “following” the defining features of the symmetry group. Therefore, triangle-y Hamiltonians would produce triangle-y decomposition.
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Interesting!
@quant_phys would you give it a try? - Näytä vastaukset
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