If you do word-level markov generation, do you have to do a transition matrix of size (dictionary)X(dictionary)? Seems...inefficient.
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Replying to @vgr
@vgr you only do it for the non-0 cases: {'word': ['next1', 'next2', next3']}1 reply 0 retweets 2 likes
Replying to @BillSeitz
@BillSeitz So an adjacency list rather than an adjacency matrix, still dict*M instead of dict^2... better I guess
1:12 PM - 11 Dec 2015
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