@ryan_richt @davisp (n/2)^2. Proof: G has no tri: G can b partitiond -> 2set, 0 edg w/in, but any edgs btw'n. If |Sets|=n/2, max edg=(n/2)^2
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@ryan_richt @davisp (n/2)^2. Proof: G has no tri: G can b partitiond -> 2set, 0 edg w/in, but any edgs btw'n. If |Sets|=n/2, max edg=(n/2)^2