Today in little known Ruby trivia: You can't guess what each line evaluates to! Answers posted as a response to this tweet!pic.twitter.com/bXjt5jLaIc
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no idea. I'd bet on flip-flop. Add parens around the range and it works as expected
I get a "warning: integer literal in conditional range" for that. It also returns true if you do 'x=1;y=2; true if x..y'
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