0 * x = 0, Infinity * x = Infinity -- who wins? NaN it.
Did not realize that 0 * Infinity is NaN. Anyone know why that wouldn't be expected to be 0?
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x already has additional bounds in the infinity case though. Could just as easily be Infinity * x = Infinity when finite, nonzero
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because infinity itself is not a number?
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It is in IEEE754
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At first blush 0 seems the legitimate response.
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I wonder if it falls out of Infinity being used to signal overflow or division by 0
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that an implementation detail of anything times infinity being NaN? I would of guessed 0 too though.
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Anything times infinity is infinity (except 0, NaN, or -infinity)
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best guess would be because infinity is more a concept than a number. Since it's not a natural number multiplication breaks down.
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It's a special case that's directly defined though. For non-special cases, x * infinity = infinity
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