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Also is -1 not an abuse of two's complement representation?
Rust guarantees twos complement representation and unsigned underflow is well defined in C
Why is -1 an unsigned underflow in this case? I would think it's just reinterpreting the bits to mean !0, but I also haven't gotten a perfect bit twiddling mental model yet. I can see 0-1 doing it, but not -1 somehow
the signed -> unsigned conversion is defined to use unsigned's wrapping rules. -1 becomes UINT_MAX, -2 (-1 - 1) becomes UINT_MAX - 1, etc
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