You, sobbing: You can't just treat a function pointer the same as if the function had been called Me: impl Expression for fn() -> Now
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Wanting to migrate `pub struct now;` to be `pub fn now() -> Now`, but that would break existing code... Unless I write `impl Expression for fn() -> Now` for every trait needed...
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Where's my slap YESSSSSSSS button?
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This is missing an 'all of the above' answer.
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I have decision paralysis
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