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It will help. My goal here is to avoid breaking JSX lines. I have: {chooseable.kind === "lesson"&& ... You propose this, which is shorter: isLesson(chooseable) && ... But what I really want is: isLesson && ...
Yeah, I don't think it's possible to get exactly that (since once it's assigned it's a bool and no longer a type guard). This is one other option though? const definitelyB = b.kind === "b" && b; definitelyB && takesB(definitelyB);
It is! And it says exactly what it means without any fancy language features! Thank you!
Any time :)
is there a reason this works but it doesn't work if you try to put the conditionals inline?
(Not an expert in TS, this is just my understanding. Take it with a grain of salt). `const b = aOrB.kind ==="b" && b` assigns a new variable with a known type of `B`. `const isB = b.kind === "b"` assigns a variable of type `boolean` not `b is B`.
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