Easiest way to prove this: As someone to make `RefMut` a functor. It immediately shows why Rust doesn't fit into Haskell's model
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Replying to @withoutboats
I can't tell if we agree or disagree from this >_<
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Replying to @withoutboats
Hah glad to hear it :) 
4:58 PM - 9 Aug 2018
from Albuquerque, NM
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