@St_Rev I have a math question - what is the reason why, for there to be a mixed strategy in a Nash situation, the strategies being mixed...
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Replying to @sarahdoingthing
@St_Rev ...have to be equal in expected value when considered independently?1 reply 0 retweets 0 likes -
Replying to @sarahdoingthing
@St_Rev (even though they are often mixed at a ratio other that 50/50)?1 reply 0 retweets 0 likes -
Replying to @sarahdoingthing
@sarahdoingthing Not sure. Here's a wild guess though: suppose they're at 60/40.1 reply 0 retweets 0 likes -
Replying to @St_Rev
@sarahdoingthing You can model THAT in turn as an 80% chance to have a 50-50 strategy, and a 20% chance to choose option 1.2 replies 0 retweets 1 like
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