@St_Rev I have a math question - what is the reason why, for there to be a mixed strategy in a Nash situation, the strategies being mixed...
@St_Rev ...have to be equal in expected value when considered independently?
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@St_Rev (even though they are often mixed at a ratio other that 50/50)? -
@sarahdoingthing Not sure. Here's a wild guess though: suppose they're at 60/40. - 2 more replies
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