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Prikvačeni tweet
This tweet contains exactly four As, one B, three Cs, two Ds, thirty-two Es, six Fs, one G, five Hs, twelve Is, one J, one K, three Ls, one M, twenty-one Ns, sixteen Os, one P, one Q, five Rs, twenty-five Ss, twenty-one Ts, two Us, seven Vs, nine Ws, five Xs, six Ys, and one Z.
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One of those apt juxtapositions that Twitter occasionally throws up.pic.twitter.com/1g9z64wl0d
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I don’t agree – I think the 10,000 year clock is a better use of time than most of the things people do – but this article is well-written and thought-provoking.https://www.wired.com/story/the-10000-year-clock-is-a-waste-of-time/ …
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Robin Houston proslijedio/la je Tweet
Here it is!! To me this is so good
#gif#creativecoding#javascriptpic.twitter.com/olApljDTuaHvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi -
Robin Houston proslijedio/la je Tweet
[1/2] Now that the ingenious
@ChocoLinkage has posted linkages that compute both squares and cubes, I thought it would be fun to reverse-engineer the squaring one. If you want to work through this in detail yourself, note that all lengths are multiples of 1/16. The magic here…pic.twitter.com/K9xVNUuWSCPrikaži ovu nitHvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi -
I just found out that there’s a clever, fairly new algorithm for multiplying matrices by Karstadt and Schwartz that looks like it might be faster in practical situations. https://www.cse.huji.ac.il/~elayeek/matmulfaster.pdf … Sadly it looks as though they have patented it. https://patentscope.wipo.int/search/en/detail.jsf?docId=US219388644 …
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Robin Houston proslijedio/la je Tweet
#OnThisDay 1961: Alan Whicker got lost in Northumberland.pic.twitter.com/7mT1ybmejx"This is number two, and this is number eight..."Hvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi -
Robin Houston proslijedio/la je Tweet
The linkages that
@ChocoLinkage comes up with are amazing! Having animated some graphs myself, I know how tricky it can be to find nice paths through the configuration space … but@ChocoLinkage keeps inventing new and delightful examples.https://twitter.com/ChocoLinkage/status/1221407779648200707 …
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Robin Houston proslijedio/la je Tweet
At the very least, I learned that the Fourier coefficients of (the natural parametrization of the boundary of) the Mandelbrot set are rational, which I think is wonderful.https://twitter.com/gro_tsen/status/1221534137292591106 …
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Robin Houston proslijedio/la je TweetHvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi
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So p is the sum of a square and four times a square – but four times a square is still a square!
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Now consider the transformation that rotates the windmill arms by 90°. This doesn’t change the area either. Since there are an odd number of windmills of area p, the arm-rotation transformation must also have a fixed point, i.e. there must be a windmill with square arms.
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So… if p = 4k + 1 is prime, there are an *odd* number of windmills with area p.
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There is at most one cross-shaped windmill with a given prime area, since the width of the arms must divide the total area (of a cross-shaped windmill). If p = 4k + 1 then there exists a cross-shaped windmill of area p (with four arms of width 1 and length k).
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The idea, briefly, is: The transformation illustrated transforms every windmill to a different windmill of the same area; cross-shaped windmills (whose arms are the same width as the central square) are mapped to themselves.
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This was posted to Math Overflow in 2018, but I just found it via a comment on
@Mathologer’s video https://www.youtube.com/watch?v=DjI1NICfjOk …, which also explains this proof.Prikaži ovu nitHvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi -
You know Zagier’s brilliant-but-baffling “one sentence proof” that every prime of the form 4k+1 is the sum of two squares? It turns out there’s a lovely intuitive explanation of it! https://mathoverflow.net/a/299696/8217 pic.twitter.com/uoSLHwjbF5
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I was wondering whether anyone has conducted an experimental test of the hypothesis that a rolling stone gathers no moss. It turns out
@MythBusters have done more or less the experiment I was imagining, and confirmed the hypothesis. http://kwc.org/mythbusters/2005/05/mythbusters_breaking_glass_a_r.html …Hvala. Twitter će to iskoristiti za poboljšanje vaše vremenske crte. PoništiPoništi -
Robin Houston proslijedio/la je Tweet
[1/2] My new eBook, INSTANTIATION, has 11 stories: • “The Discrete Charm of the Turing Machine” • “Zero For Conduct” • “Uncanny Valley” • “Seventh Sight” • “The Nearest” • “Shadow Flock” • “Bit Players” • “Break My Fall” • “3-adica” • “The Slipway” • “Instantiation”pic.twitter.com/2uveQZgWto
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An intriguing mystery I know nothing about – but maybe one of my clever & knowledgeable followers has some insight?https://twitter.com/gro_tsen/status/1220440657766035463 …
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Robin Houston proslijedio/la je Tweet
This, my Numberphile debut, is about van der Waerden's theorem, including a proof (presented informally of course) for the case of two colours and progressions of length 3. It was fun to do, and my interviewer
@BradyHaran added some beautiful graphics afterwards, as is his wont.https://twitter.com/numberphile/status/1219602384130859008 …
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