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revodavid's profile
David Smith
David Smith
David Smith
@revodavid

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David Smith

@revodavid

Cloud Advocate at Microsoft. Tweets about AI, Data Science, R #rstats and other things I love: culture, politics, gaming, my husband @nonfamousjay. He/him.

Chicago, IL
blog.revolutionanalytics.com
Joined April 2009

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    David Smith‏ @revodavid 12 Sep 2018

    Histogram of P-values (rounded, presumably, to the nearest 0.01) published in millions of scientific studies. Hmm. Great, provocative talk by @StatGarrett at #earlconfpic.twitter.com/42MegOhjsQ

    2:30 AM - 12 Sep 2018
    • 385 Retweets
    • 827 Likes
    • Jennifer Jiang jorge luiz correa Lara Bluhm Katerina Maschenko Aron Roberts XbMPr みちこ Adán Romero👨🏽‍💻 Kossy🇹🇭
    30 replies 385 retweets 827 likes
      1. New conversation
      2. Frank Harrell‏ @f2harrell 12 Sep 2018
        Replying to @revodavid @StatGarrett

        Not rounding would make it even more interesting.

        1 reply 0 retweets 11 likes
      3. Stuart Buck‏ @StuartBuck1 12 Sep 2018
        Replying to @f2harrell @revodavid @StatGarrett

        The p-value for this distribution of p-values having occurred by chance is zero, I'd bet.

        2 replies 0 retweets 37 likes
      4. rogier kievit‏ @rogierK 13 Sep 2018
        Replying to @StuartBuck1 @f2harrell and

        But isn’t the problem with these recurring plots that text scrapers count <0.05 as 0.05?

        1 reply 0 retweets 11 likes
      5. rogier kievit‏ @rogierK 13 Sep 2018
        Replying to @rogierK @StuartBuck1 and

        @lakens has written about this so can say more (I might be wrong)

        1 reply 0 retweets 2 likes
      6. Daniël Lakens‏Verified account @lakens 13 Sep 2018
        Replying to @rogierK @StuartBuck1 and

        This plot is completely uninformative. So sad to see it being retweeted like this. Means scientists are clueless about the real problem. This is indeed p<.05. See Lakens, 2014, 2015 why it is dfficult to learn anything from these analyses.

        3 replies 2 retweets 20 likes
      7. Lucio Martelli‏ @LucioMM1 13 Sep 2018
        Replying to @lakens @rogierK and

        Elaborate more pls. This plot clearly signals fraud imho

        2 replies 0 retweets 0 likes
      8. rogier kievit‏ @rogierK 13 Sep 2018
        Replying to @LucioMM1 @lakens and

        Nope

        1 reply 0 retweets 1 like
      9. 3 more replies
      1. New conversation
      2. Michael Moutoussis‏ @M_Moutoussis 20 Sep 2018
        Replying to @revodavid @o_guest @StatGarrett

        What's provocative about this slide?

        1 reply 1 retweet 3 likes
      3. rohan kapitany‏ @Psycasm 21 Sep 2018
        Replying to @M_Moutoussis @revodavid and

        p-values should be uniformly distributed under the null (flat distribution). If there is a real effect, p-values should cluster closer to 0. That there is a magnificent spike at .05 suggest that there is some serious p-hacking and selecting reporting/publishing going on...

        0 replies 2 retweets 9 likes
      4. End of conversation
      1. New conversation
      2. Phil Wolff 马爱狼  🐺‏ @evanwolf 12 Sep 2018
        Replying to @revodavid @StatGarrett

        I asked my stats teachers why 5% was the number for "significance." A one-in-twenty chance that you're wrong seems high for so many uses. From junior high through college, all said "that's just the number." Textbooks skimped on this too, leaving it context-free. Balderdash.

        2 replies 0 retweets 3 likes
      3. Zachary Nichols‏ @zacknichols0 13 Sep 2018
        Replying to @evanwolf @revodavid @StatGarrett

        Nitpick: it's not 1 in 20 chance you're wrong, it's 1 in 20 chance that you could get a result as strong as you got under the null hypothesis. That distinction is part of the reason I think Bayesian approaches make more sense in many applications -- they better match intuition

        1 reply 1 retweet 9 likes
      4. Lucio Martelli‏ @LucioMM1 13 Sep 2018
        Replying to @zacknichols0 @evanwolf and

        As strong, OR STRONGER

        0 replies 0 retweets 2 likes
      5. End of conversation
      1. Max Little‏ @MaxALittle 12 Sep 2018
        Replying to @revodavid @StatGarrett

        Very disturbing. Figures from this study, I believe: https://www.ncbi.nlm.nih.gov/pubmed/26978209 

        0 replies 1 retweet 7 likes
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      1. New conversation
      2. mt‏ @mtobis 13 Sep 2018
        Replying to @revodavid @StatGarrett

        I don't know that there's anything sinister here. If you have a real effect, you can keep expending resources to increase N until you can show it.

        2 replies 0 retweets 2 likes
      3. Victor Venema‏ @VariabilityBlog 13 Sep 2018
        Replying to @mtobis @revodavid @StatGarrett

        If you keep on gathering data until your p<0.05, then your p-value is not a good estimate of p due to multiple testing.

        1 reply 0 retweets 4 likes
      4. mt‏ @mtobis 13 Sep 2018
        Replying to @VariabilityBlog @revodavid @StatGarrett

        Not really versed in frequentist thinking, but my understanding is not that p is a real thing you're estimating, but a property of your data & null hypotheses. Hence, more independent data can reduce p to significance. Am I missing something?

        1 reply 0 retweets 1 like
      5. Victor Venema‏ @VariabilityBlog 13 Sep 2018
        Replying to @mtobis @revodavid @StatGarrett

        More data is good. But if you test multiple times where you already have enough data you have each time a chance to have a result that is too significant by chance, while p is supposed to protect you from getting a result by chance. That is the multiple testing problem. 1/2

        1 reply 0 retweets 2 likes
      6. Victor Venema‏ @VariabilityBlog 13 Sep 2018
        Replying to @VariabilityBlog @mtobis and

        To take an example from climate. If you have a reason to test the trend for a certain period, the error of your regression parameters will be right. But you increase your chance to find a "hiatus" by testing all possible begin years. Then the p-value is no longer right. 2/2

        2 replies 0 retweets 0 likes
      7. Victor Venema‏ @VariabilityBlog 13 Sep 2018
        Replying to @VariabilityBlog @mtobis and

        Surely also in Bayesian statistics the same problem with https://en.wikipedia.org/wiki/Multiple_comparisons_problem … exists.

        0 replies 0 retweets 3 likes
      8. End of conversation

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