I mean, just to begin with: LOOSE equality? In 2018? No linter?
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The correct answer to this SO question is "Yes, but I don't want to work for an organisation where it can" https://stackoverflow.com/questions/48270127/can-a-1-a-2-a-3-ever-evaluate-to-true …
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Or C++, for that matter.
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Well, yeah, it's an absolutely trivial question in any language with threads or operator overloading
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If a = {valueOf:function() {return Math.floor(Math.random()*3+1);}}, then the expression usually won't evaluate to true, but it sometimes will.
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Also, in Haskell you can overload what 1, 2, and 3 mean: instance Num () where fromInteger _ = () a = ()
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Reminds me of my (sadly incorrect) response to "f(f(n) == -n" https://www.reddit.com/r/programming/comments/1h0r6z/design_a_function_f_such_that_ffn_n/caprpvz/?context=3 …
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the Hangul answer is so good.
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fsck tapas crypt
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Is a an iterator?
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this can also work in Python.
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Yeah, but in Python you can do it in a *sane* way (an object that is equal to multiple integers is saner than an object whose conversion operators are stateful according to my arbitrary scale)
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