Note that it isn't necessary to for the trolls threaten the *entire* board (which I don't think is possible even with nine of them)...
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Replying to @qntm
Since the lone dwarf *must* move, it suffices to threaten the whole board except for one square...
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Replying to @qntm
Or, better yet, to threaten the entire board except for a network of squares, no two of which are connected by a dwarf's move.
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Replying to @qntm
The fact that a troll, too, must be moved may complicate the actual procedure of assembling this trap.
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Replying to @qntm
Anyway, here's one of several solutions I found using nine trolls. You can see why I think there's a solution for eight here somewherepic.twitter.com/OhCSUYKeyn
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Replying to @qntm
I feel as if I'm missing something obvious but I've given a few hours to this and I don't think it's happening tonight.
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Replying to @qntm
In a recent game I conceded I wasn't likely to capture the last dwarf with only seven trolls...
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Replying to @qntm
I still think I could have got 'em, if I forced my opponent to keep playing for another few hours
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Replying to @qntm
Since the rules say BOTH players must concede that no further captures are possible, this is a practical technique with as few as one troll
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Replying to @qntm
The problem is more complex for dynamic, mobile arrangements of trolls instead of static collections. Herding-based solutions?
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Maybe create two large "disconnected" regions of unthreatened space, then gradually close the one with the trapped dwarf?
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