Note that S(7) is apparently more than 10^10^10^10^10^10^7, so S(4888) is probably a FAIRLY large number of steps to run for
-
-
-
@qntm full employment theorem for mathematicians right there
End of conversation
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.