quarantine 'em on Twitter: "I could be dead wrong about this but I'm fairly sure Kruskal's TREE function is computable with much less than a ~120 state Turing Machine https://t.co/X434QvswIO"

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quarantine 'em Retweeted

Until November 2017 this was indeed the largest number which could fit in a Tweet... when expressed in Base 1 https://twitter.com/__vlqc/status/1165770501412806656 …

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This Tweet is unavailable.

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted quarantine 'em

Old joke from the Look Around You episode on "Maths"https://twitter.com/qntm/status/1165726300805505024 …

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quarantine 'em @qntm

The largest number is forty-five billion. But mathematicians believe there may be even larger ones

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted Nate

This is the only submitted number whose position I'm genuinely uncertain of. Kruskal's weak tree function is extremely fast-growing, but tree(3) is relatively small, with lower bounds in the quadrillions range. Placement here is tentativehttps://twitter.com/heyandy889/status/1165749618044493824 …

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Nate @heyandy889

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tree(3)

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted fabs();

This isn't well-defined, but in most scenarios your mum is at least contained within the observable universe, so this is bounded above by about a googolhttps://twitter.com/raspofabs/status/1165781895734530051 …

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fabs(); @raspofabs

Replying to @qntm

The number of atoms making up your mum in a your mum is so fat joke.

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted Ⓒⓐⓜⓔⓡⓞⓝ Ⓓⓔⓥⓘⓝⓔ

I'm not 100% certain what the leading exclamation mark here is for, but ignoring that, there are 277 nines, so that's 10^(10^277 - 1), slightly more than a googolplexhttps://twitter.com/Cameron__Devine/status/1165850650279739392 …

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Ⓒⓐⓜⓔⓡⓞⓝ Ⓓⓔⓥⓘⓝⓔ @Cameron__Devine

Replying to @qntm

!1e9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

3 replies 0 retweets 5 likes

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted Natan Melzer

In Knuth's arrow notation this is "99↑↑89"... except that "base 9^999" means we read "99" as 9 * 9^999 + 9 in decimal, and "89" as 8 * 9^999 + 9 in decimal. So that's a little less than (10↑1000)↑↑↑2. Three arrows. Sizeable...https://twitter.com/NatanMelzer/status/1166376298559758336 …

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Natan Melzer @NatanMelzer

Replying to @qntm

99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99 base 9^999

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted Wayne Werner

If by "And so on" we assume that the nines continue for the remainder of the Tweet, that's 276 nines. That's still three arrows, but a MUCH larger exponenthttps://twitter.com/waynejwerner/status/1165837725410504704 …

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Wayne Werner @waynejwerner

Replying to @qntm

9^^^99999999999999999999999... And so on

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted halcanary

haha Knuth up-arrows go brrrhttps://twitter.com/halcanary/status/1165734655292837890 …

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halcanary @halcanary

Replying to @qntm

Using Knuth's up-arrow notation: 2↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑8

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted tef e.books, depressed birb fan

Nobody specifically entered Graham's number, but this is slightly bigger than that, and easily outclasses any expression using a small, writeable number of up-arrowshttps://twitter.com/tef_ebooks/status/1165725289705607169 …

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tef e.books, depressed birb fan @tef_ebooks

Replying to @qntm

ackerman's function fed with grahams number, then passed into ackerman's function again, graham's number of times, plus one

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted Lost Snowdrift

This is a pretty large number. Kruskal's much faster-growing TREE function is such that TREE(3) obliterates Graham's number in terms of scale. This, however, is TREE^41(420)https://twitter.com/LostSnowdrift/status/1166096988904906752 …

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Lost Snowdrift @LostSnowdrift

Replying to @qntm

TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(420)))))))))))))))))))))))))))))))))))))))))? https://en.wikipedia.org/wiki/Kruskal%27s_tree_theorem#TREE(3) …

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quarantine 'em‏ @qntm Apr 17

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quarantine 'em Retweeted d ⧉ aan

I could be dead wrong about this but I'm fairly sure Kruskal's TREE function is computable with much less than a ~120 state Turing Machinehttps://twitter.com/ijks_w/status/1165727070305038337 …

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d ⧉ aan @ijks_w

Replying to @qntm

to get low-hanging fruit: the Nth Busy Beaver number, where N is the number of characters in this tweet - as explained in https://www.scottaaronson.com/writings/bignumbers.html …

3:37 PM - 17 Apr 2020

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