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qntm's profile
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@qntm

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quarantine 'em

@qntm

I created the Antimemetics Division. http://scp-wiki.wikidot.com/antimemetics-division-hub …

qntm.org
Joined September 2009

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    1. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Addison "Why're there still Nazis here, Jack" Fox

      Sadly the previous competitor is already eclipsed by an immense, impossible-to-calculate factorhttps://twitter.com/DaMullet/status/1165726181020327938 …

      quarantine 'em added,

      Addison "Why're there still Nazis here, Jack" Fox @DaMullet
      Replying to @qntm
      I'm gonna go with six
      1 reply 0 retweets 25 likes
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    2. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted

      Until November 2017 this was indeed the largest number which could fit in a Tweet... when expressed in Base 1 https://twitter.com/__vlqc/status/1165770501412806656 …

      quarantine 'em added,

      This Tweet is unavailable.
      1 reply 0 retweets 12 likes
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    3. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted quarantine 'em

      Old joke from the Look Around You episode on "Maths"https://twitter.com/qntm/status/1165726300805505024 …

      quarantine 'em added,

      quarantine 'em @qntm
      The largest number is forty-five billion. But mathematicians believe there may be even larger ones
      Show this thread
      2 replies 0 retweets 13 likes
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    4. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Nate

      This is the only submitted number whose position I'm genuinely uncertain of. Kruskal's weak tree function is extremely fast-growing, but tree(3) is relatively small, with lower bounds in the quadrillions range. Placement here is tentativehttps://twitter.com/heyandy889/status/1165749618044493824 …

      quarantine 'em added,

      Nate @heyandy889
      Replying to @qntm
      tree(3)
      1 reply 0 retweets 9 likes
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    5. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted fabs();

      This isn't well-defined, but in most scenarios your mum is at least contained within the observable universe, so this is bounded above by about a googolhttps://twitter.com/raspofabs/status/1165781895734530051 …

      quarantine 'em added,

      fabs(); @raspofabs
      Replying to @qntm
      The number of atoms making up your mum in a your mum is so fat joke.
      2 replies 0 retweets 12 likes
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    6. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Ⓒⓐⓜⓔⓡⓞⓝ Ⓓⓔⓥⓘⓝⓔ

      I'm not 100% certain what the leading exclamation mark here is for, but ignoring that, there are 277 nines, so that's 10^(10^277 - 1), slightly more than a googolplexhttps://twitter.com/Cameron__Devine/status/1165850650279739392 …

      quarantine 'em added,

      Ⓒⓐⓜⓔⓡⓞⓝ Ⓓⓔⓥⓘⓝⓔ @Cameron__Devine
      Replying to @qntm
      !1e9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
      3 replies 0 retweets 5 likes
      Show this thread
    7. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Natan Melzer

      In Knuth's arrow notation this is "99↑↑89"... except that "base 9^999" means we read "99" as 9 * 9^999 + 9 in decimal, and "89" as 8 * 9^999 + 9 in decimal. So that's a little less than (10↑1000)↑↑↑2. Three arrows. Sizeable...https://twitter.com/NatanMelzer/status/1166376298559758336 …

      quarantine 'em added,

      Natan Melzer @NatanMelzer
      Replying to @qntm
      99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99^99 base 9^999
      1 reply 0 retweets 4 likes
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    8. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Wayne Werner

      If by "And so on" we assume that the nines continue for the remainder of the Tweet, that's 276 nines. That's still three arrows, but a MUCH larger exponenthttps://twitter.com/waynejwerner/status/1165837725410504704 …

      quarantine 'em added,

      Wayne Werner @waynejwerner
      Replying to @qntm
      9^^^99999999999999999999999... And so on
      1 reply 0 retweets 4 likes
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    9. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted halcanary

      haha Knuth up-arrows go brrrhttps://twitter.com/halcanary/status/1165734655292837890 …

      quarantine 'em added,

      halcanary @halcanary
      Replying to @qntm
      Using Knuth's up-arrow notation: 2↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑↑8
      2 replies 4 retweets 39 likes
      Show this thread
    10. quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted tef e.books, depressed birb fan

      Nobody specifically entered Graham's number, but this is slightly bigger than that, and easily outclasses any expression using a small, writeable number of up-arrowshttps://twitter.com/tef_ebooks/status/1165725289705607169 …

      quarantine 'em added,

      tef e.books, depressed birb fan @tef_ebooks
      Replying to @qntm
      ackerman's function fed with grahams number, then passed into ackerman's function again, graham's number of times, plus one
      1 reply 0 retweets 8 likes
      Show this thread
      quarantine 'em‏ @qntm Apr 17
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      quarantine 'em Retweeted Lost Snowdrift

      This is a pretty large number. Kruskal's much faster-growing TREE function is such that TREE(3) obliterates Graham's number in terms of scale. This, however, is TREE^41(420)https://twitter.com/LostSnowdrift/status/1166096988904906752 …

      quarantine 'em added,

      Lost Snowdrift @LostSnowdrift
      Replying to @qntm
      TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(TREE(420)))))))))))))))))))))))))))))))))))))))))? https://en.wikipedia.org/wiki/Kruskal%27s_tree_theorem#TREE(3) …
      3:35 PM - 17 Apr 2020
      • 1 Retweet
      • 9 Likes
      • nop3 Jesin🌹 of Antifa pete Mike Weatherford🎃 Nick C. rebecca 🐶 prototype27 Jean-Marc Liotier
      2 replies 1 retweet 9 likes
        1. New conversation
        2. quarantine 'em‏ @qntm Apr 17
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          quarantine 'em Retweeted d ⧉ aan

          I could be dead wrong about this but I'm fairly sure Kruskal's TREE function is computable with much less than a ~120 state Turing Machinehttps://twitter.com/ijks_w/status/1165727070305038337 …

          quarantine 'em added,

          d ⧉ aan @ijks_w
          Replying to @qntm
          to get low-hanging fruit: the Nth Busy Beaver number, where N is the number of characters in this tweet - as explained in https://www.scottaaronson.com/writings/bignumbers.html …
          1 reply 0 retweets 4 likes
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        3. quarantine 'em‏ @qntm Apr 17
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          quarantine 'em Retweeted Linus Hamilton

          This value is smaller than, but probably in the vicinity of, BB(9999) in terms of scale, therefore far surpassing BB(120) abovehttps://twitter.com/linyks/status/1165748190890483712 …

          quarantine 'em added,

          Linus Hamilton @linyks
          Replying to @qntm
          9999th Busy Beaver number for alternating Turing Machines (TMs with choices made alternately by Alice, who wants to prolong execution, and Bob, who wants to cut it short).
          1 reply 0 retweets 4 likes
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        4. quarantine 'em‏ @qntm Apr 17
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          quarantine 'em Retweeted pete

          The Radó maximum shift function is closely related to BB in terms of growth rate but this is the first entry to start using such functions recursively instead of just passing in basic literal numbers. Excellent callhttps://twitter.com/mcallisterjp/status/1166353418002284545 …

          quarantine 'em added,

          pete @mcallisterjp
          Replying to @qntm
          xₛ₍₉₉₎, such that x₀=s(99); xₙ=s^xₙ₋₁(xₙ₋₁); s=Radó maximum shift function; ^=function iteration
          1 reply 0 retweets 9 likes
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        5. quarantine 'em‏ @qntm Apr 17
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          quarantine 'em Retweeted Drake Thomas

          Not 100% certain that this is the winner but it looks suspiciously similar in construction to Rayo's number, which won a large number duel at MIT. Well donehttps://twitter.com/MaskedTorah/status/1167006809296531456 …

          quarantine 'em added,

          Drake Thomas @MaskedTorah
          Replying to @qntm
          F(n) = Max number uniquely defined by a sentence in PA in the standard model with at most n chars. F1(n) = same as F but where language of PA has the function F. F2 for F1&F, etc. Fw = PA with access to a symbol F_m(n). Then # is Fw(BB(BB(BB(BB(BB(BB(BB(BB(BB(BB(BB(99))))))))))))
          2 replies 0 retweets 15 likes
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        6. quarantine 'em‏ @qntm Apr 17
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          Now to take a big sip of coffee and assume I made no errors whatsoever

          2 replies 0 retweets 27 likes
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        7. End of conversation
        1. ralph waldo cybersyn (cw: police violence in RTs)‏ @atomicthumbs Apr 17
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          Replying to @qntm

          ralph waldo cybersyn (cw: police violence in RTs) Retweeted ralph waldo cybersyn (cw: police violence in RTs)

          thanks to both of you for the inspirationhttps://twitter.com/atomicthumbs/status/1251279702251065345 …

          ralph waldo cybersyn (cw: police violence in RTs) added,

          ralph waldo cybersyn (cw: police violence in RTs) @atomicthumbs
          TREE(1): Mastered. TREE(2): MAstered. TREE(3): Heres when they start trying to trick you
          0 replies 0 retweets 0 likes
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