I was told last night that type `A with B` != `B with A` even though each subtypes t'other. I'm not convinced. Can anyone explain it to me?
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Replying to @propensive
due to linearization they can differ under projection, which is unsound.pic.twitter.com/uh6mWaJhd3
2 replies 8 retweets 27 likes
Replying to @tpolecat
Perfect, thank you! So it's all because type members get clobbered.
3:32 AM - 4 Apr 2017
0 replies
0 retweets
2 likes
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