@propensive It is. Replace c.Expr[...] with c.Tree and you are good to go.
Is it possible to write an dependently-typed macro? def foo(x: X): x.Type = macro fooImpl def fooImpl(c: Context)(x: c.Expr[X]): c.Expr[�]
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@den_sh Thanks! Looks like I *might* be able to get this to work... :)
End of conversation
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@propensive So that's what you're doing over there...Thanks. Twitter will use this to make your timeline better. UndoUndo
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