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propensive's profile
Jon Pretty
Jon Pretty
Jon Pretty
@propensive

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Jon Pretty

@propensive

Supporting Scala through professional training and open-source software. Responsible for Magnolia, Fury, Scala World and Functional Africa.

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propensive.com
Joined July 2010

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    1. Julien Tournay‏ @skaalf Feb 11

      Silly question of the day: Is there a way in #scala3 to "unpack" a String at the type level ? ie: val x: Unpack["abc"] = ('a', 'b', 'c')

      2 replies 0 retweets 4 likes
    2. Jon Pretty‏ @propensive Feb 11
      Replying to @skaalf

      Yes, you can match on the type parameter's TypeRepr as a ConstantType(StringConstant(str)) and then just work on the string.

      1 reply 0 retweets 1 like
    3. Julien Tournay‏ @skaalf Feb 11
      Replying to @propensive

      Ah I see. I can give it a try :) Any non-macro solution ?

      1 reply 0 retweets 0 likes
    4. Jon Pretty‏ @propensive Feb 11
      Replying to @skaalf

      For some reason I read the word "macro" in your question, but maybe that's what happens when you've been doing Scala 3 macros all day...

      2 replies 0 retweets 1 like
    5. Julien Tournay‏ @skaalf Feb 11
      Replying to @propensive

      Yeah I was expecting it to be feasible using a Match Type but maybe I was too optimistic :)

      1 reply 0 retweets 0 likes
      Jon Pretty‏ @propensive Feb 11
      Replying to @skaalf

      There's also scala.compiletime.ops.string.+, but I'm not sure how it uniquely deconstructs a String.

      7:14 AM - 11 Feb 2021
      1 reply 0 retweets 0 likes
        1. Julien Tournay‏ @skaalf Feb 11
          Replying to @propensive

          It does not 😊

          0 replies 0 retweets 1 like
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