What's the best option in #Scala for parsing XML?
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worth a mention - not kept up to date though - https://github.com/ScalaWilliam/xs4s … - if you're reading a large XML file. Otherwise I use scala-xml, but you gotta be careful with URIs as see by other responses to Alex's tweet.
1 reply 0 retweets 3 likes -
Replying to @ScalaWilliam @alexelcu
I updated xs4s! https://github.com/ScalaWilliam/xs4s/blob/master/README.md#capabilities … also cc
@propensive this was possible with an immutable approach xs4s.XML.loadString("<test/>") gets you a scala.xml.Elem Would be great to get feedback and check if there are any issues!1 reply 0 retweets 2 likes
I will definitely take a look before I try to do any more work on my attempt. (Not sure when I will find time for that, though...)
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