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propensive's profile
Jon Pretty
Jon Pretty
Jon Pretty
@propensive

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Jon Pretty

@propensive

Supporting Scala through professional training and open-source software. Responsible for Magnolia, Fury, Scala World and Functional Africa.

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propensive.com
Joined July 2010

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    1. Wiem 2.4-RC-2603‏ @WiemZin 29 Feb 2020

      reflective calls in #scala: trait A { def add(a: Int, b: Int): Int = a + b ... } trait B { def add(a: Int, b: Int): Int = a + b ... } def addOne(t: {def add(a: Int, b: Int): Int}, a: Int): Int = t.add(a, 1) addOne(new A{}, 3) addOne(new B{}, 3)

      3 replies 0 retweets 15 likes
    2. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020
      Replying to @WiemZin

      Reflective? What you’re showing is called structural typing, not reflective calls, isn’t it?

      1 reply 0 retweets 1 like
    3. Ryan‏ @ryanb93 29 Feb 2020
      Replying to @NicolasRinaudo @WiemZin

      Structural types rely on runtime reflection.

      1 reply 0 retweets 4 likes
    4. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020
      Replying to @ryanb93 @WiemZin

      They do (although not always, in dotty), but it seems a bit misleading. So does pattern matching and it’d be weird to call that reflexion.

      2 replies 0 retweets 1 like
    5. Wiem 2.4-RC-2603‏ @WiemZin 29 Feb 2020
      Replying to @NicolasRinaudo @ryanb93

      From the documentation: a reflective call is needed when accessing a structural type: https://www.scala-lang.org/api/current/scala/language$.html#reflectiveCalls:languageFeature.reflectiveCalls … and yes, the example shows how to use structural types

      1 reply 0 retweets 0 likes
    6. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020
      Replying to @WiemZin @ryanb93

      Sure, it just seemed weird to me to call that reflective call when that’s merely an implementation detail of the actual feature - like pattern matching uses reflective calls as well, yet it’s called pattern matching. If that’s what you meant though, no problem

      0 replies 0 retweets 3 likes
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    8. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020

      val oa: Option[A]= ??? oa match { case Some(a) => ??? case None => ??? } Some.unapply is of type Some[A] => Some[A], I’m not sure how to call it on an Option[A] without first checking the types line up at runtime, then calling unapply through reflection.

      1 reply 0 retweets 0 likes
    9. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020
      Replying to @NicolasRinaudo @WiemZin @ryanb93

      Note that currently being at the hospital without a computer, I can’t double check any of this and am doing it from memory. Might be mistakes in my reasoning or memory, and I’d be happy to have them corrected.

      2 replies 0 retweets 0 likes
      Jon Pretty‏ @propensive 29 Feb 2020
      Replying to @NicolasRinaudo @WiemZin @ryanb93

      I think the point is that it's reflection, but not a reflective call. A cast doesn't count.

      10:50 PM - 29 Feb 2020
      1 reply 0 retweets 0 likes
        1. New conversation
        2. Nicolas Rinaudo‏ @NicolasRinaudo 29 Feb 2020
          Replying to @propensive @WiemZin @ryanb93

          I’m not talking about a cast though. Finding the right unapply method is not a cast. Dynamically applying it to the input is not a cast. I’m open to the idea that none of this happens, but I think it does

          0 replies 0 retweets 0 likes
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