There are 100 prisoners, numbered 1-100. The prisoners' numbers are written onto 100 cards, put randomly into 100 envelopes numbered 1-100. They can't communicate, but are invited, one by one, to open 50 envelopes. If any prisoner fails to find his number, they all get killed.
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At best, there's a 50% chance any one prisoner can find his number. It would seem like there's a probability of (½)¹⁰⁰ or 0.00000000000000000000000000008% that every prisoner could find his own number, if each were to check 50 envelopes at random.
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They could certainly do even worse than this. If they all agreed in advance to open envelopes 1-50, then fifty of them would be guaranteed never to find their number and they'd all die. But could they come up with a strategy in advance which would improve their survival chances?
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What makes this my favourite combinatorics problem is that there *is* a strategy which increases their likelihood of survival from 0.00000000000000000000000000008% to about 30%. So, what is the strategy, and why does it work?
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Replying to @propensive
Can the prisoners outside measure the time each one spends in the room?
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Replying to @propensive
Ok
can all prisoners have a meeting before entering the room and agree on a strategy? I feel like they should try to overlap the envelopes each opens the least possible. So if I'm prisoner 1, I open 1-50, prisoner 2 something else etc.2 replies 0 retweets 0 likes
Yes, they can discuss their strategy beforehand, but not once the envelope-opening has started. Your strategy would achieve the same probability as the random-opening strategy, and would avoid the guaranteed-failure scenario. But they can do *much* better.
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