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That (or the isomorphic strategy) would be the perfect strategy for two prisoners, and they would have a 50% chance of survival.
Work toward the middle? So prisonor 1 opens 1 and 4?
They open the envelope matching their position in line and the next even or odd envelope. After: 1: 1 or 3 contains 1 After: 2: 2 or 4 contains 2 After: 3. 3 or 1 contains 3 Prisoner 4: 3 and 1 are definitely not it
By the time prisoner 51 comes along envelopes 1 - 50 would be eliminated already in this case?
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