cat +table-turtle =170 turtle+table-cat=130 2*table=300 table=150
In this odd problem, is there any way to determine the height of the animals? (It is claimed that it's possible to determine the height of the table.) http://tinyurl.com/y96t7bzr pic.twitter.com/382YcU6Myr
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3 unknowns and two equations. After finding the height of the table one has only one equation for the remaining two variables so it's not possible to decide each animal's height
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What's odd about the problem? That's how I always measure tables.
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For some reason I'm getting the cat as 40cm and the tortoise as 20cm (assuming the table is 150cm)
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But anything with a 20cm difference between the two would work
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Kat is 40cm en omdat de som (300cm) van deze plaatjes 2 tafels is, is de tafel 150cm en de schildpad dus 20cm.pic.twitter.com/nDMg9JI1wi
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Of course there is. Table height is solved by simple algebra (150 cm). From which the rest follows.
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All that follows is that the cat is 20cm taller than the turtle. It simplifies to 1 equation with 2 unknowns so you can’t determine the actual heights of the animals, only the relationship between their heights.
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Novi razgovor -
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cat is 20 cm taller than tortoise.
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Table height = 150cm No, the two equations are degenerate. You just know that the cat is 20cm taller than the turtle. Love this problem!!
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Čini se da učitavanje traje već neko vrijeme.
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