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pcwalton's profile
Patrick Walton
Patrick Walton
Patrick Walton
@pcwalton

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Patrick Walton

@pcwalton

Research engineer at Mozilla

San Francisco, CA
pcwalton.github.io
Joined November 2009

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    1. Sam Tobin-Hochstadt‏ @samth 30 Apr 2019
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      Replying to @strega_nil @graydon_pub @pcwalton

      I've written substantial programs in both SML and OCaml, and in neither one did I use the module system in a way that wouldn't work in the Haskell module system.

      2 replies 0 retweets 0 likes
    2. Patrick Walton‏ @pcwalton 30 Apr 2019
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      Replying to @samth @graydon_pub

      The one thing I kind of want is the ability to pass a trait to a singleton module without threading it around, for dependency injection. (I don’t believe in DI as a way of life, but sometimes it’s a useful pattern.) I’m not sure the ML module system is that great at DI though.

      3 replies 0 retweets 1 like
    3. Patrick Walton‏ @pcwalton 30 Apr 2019
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      Replying to @pcwalton @samth @graydon_pub

      Like, SML’s module system looks nice on paper, but I’ve worked with it in anger (at UChicago) and hated it.

      2 replies 1 retweet 1 like
    4. Patrick Walton‏ @pcwalton 30 Apr 2019
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      Replying to @pcwalton @samth @graydon_pub

      I understand what they’re trying to do, but the usability is pretty bad. More work is needed.

      1 reply 0 retweets 0 likes
    5. postmodern girl‏ @strega_nil 30 Apr 2019
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      Replying to @pcwalton @samth @graydon_pub

      I feel like the issue is using SML, an explicitly academic language - OCaml's module system is far nicer, ime.

      1 reply 0 retweets 0 likes
    6. postmodern girl‏ @strega_nil 30 Apr 2019
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      Replying to @strega_nil @pcwalton and

      SML isn't attempting to make modules very ergonomic, but OCaml has done a ton of work in that area

      1 reply 0 retweets 0 likes
    7. postmodern girl‏ @strega_nil 30 Apr 2019
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      Replying to @strega_nil @pcwalton and

      I, for example, really appreciate doing stuff like: ``` val reduce : 'a array -> (module Monoid with type t = 'a) -> 'a ```

      1 reply 0 retweets 1 like
    8. Patrick Walton‏ @pcwalton 30 Apr 2019
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      Replying to @strega_nil @samth @graydon_pub

      I don’t find that kind of thing readable at all, but reasonable people can disagree

      1 reply 0 retweets 1 like
    9. postmodern girl‏ @strega_nil 30 Apr 2019
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      Replying to @pcwalton @samth @graydon_pub

      what's not readable about that? genuinely curious.

      2 replies 0 retweets 0 likes
    10. postmodern girl‏ @strega_nil 30 Apr 2019
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      Replying to @strega_nil @pcwalton and

      (besides the backwards type application and a bit too much wordiness)

      1 reply 0 retweets 0 likes
      Patrick Walton‏ @pcwalton 30 Apr 2019
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      Replying to @strega_nil @samth @graydon_pub

      Because thinking about a module as a type is weird. By contrast, Rust: fn reduce<A, F>(&[A], F) -> A where F: Monoid<T = A> Or even better, the actual signature, which says what it *is*: fn fold<B, F>(self, init: B, f: F) -> B where F: FnMut(B, Self::Item) -> B

      8:04 PM - 30 Apr 2019
      2 replies 0 retweets 0 likes
        1. New conversation
        2. postmodern girl‏ @strega_nil 30 Apr 2019
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          Replying to @pcwalton @samth @graydon_pub

          I think this is more due to your familiarity than the actual readability of the code -- the code in OCaml gives a lot more semantic clarity, imo, and passing modules as values is not especially weird (it's common in C++ or Haskell, the latter through typeclasses)

          2 replies 0 retweets 2 likes
        3. Patrick Walton‏ @pcwalton 30 Apr 2019
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          Replying to @strega_nil @samth @graydon_pub

          I don’t expect to convince you.

          0 replies 0 retweets 0 likes
        4. End of conversation
        1. Yawar Amin‏ @yawaramin 30 Apr 2019
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          Replying to @pcwalton @samth @graydon_pub

          A module having a type and being able to refer to that type is straight up based on type theory. See https://youtu.be/oJOYVDwSE3Q?t=30m6s … (a few minutes of the video) in which @chrisamaphone explains this really neatly.

          0 replies 0 retweets 0 likes
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