More fun with C. The following code _correctly_ prints "Not one". void isOne(int i) { if (i == 1) printf("One\n"); else printf("Not one\n"); } int main() { struct { int a:1; }s; s.a = 1; isOne(s.a); return 0; }
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This is converting a constant that won't fit into the current datatype, not signed overflow. Unsigned to signed int conversion is impl-defined behavior.
Okay.. I see. If it's impl-defined then yes, that's the only correct behavior, because no matter what the impl-defined result is, int a:1 will never hold the value 1.
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I didn't think that far ahead when I thought about the other signed reprs (1 => -0)- gotta make sure my code compiles for Unisys, after all- but you're right :)
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