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oe1cxw's profile
Claire Xen 🏳️‍⚧️🏳️‍🌈🧙🏻‍♀️ BLM 🏴🚩
Claire Xen 🏳️‍⚧️🏳️‍🌈🧙🏻‍♀️ BLM 🏴🚩
Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩
@oe1cxw

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Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩

@oe1cxw

Neurodiverse trans geek girl. Yosys, RISC-V, SAT/SMT.

She/her/hers
clairexen.net
Joined September 2014

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    1. William D. Jones‏ @cr1901 11 May 2016
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      Replying to @oe1cxw

      @oe1cxw All the other peaks are just 0 :P.

      1 reply 0 retweets 0 likes
    2. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      Replying to @cr1901

      @cr1901 This does not make any sense. fyi: Kronecker Delta is 1 when i=j and 0 otherwise. I.e. identity matrix in the discrete case.

      1 reply 0 retweets 0 likes
    3. William D. Jones‏ @cr1901 11 May 2016
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      Replying to @oe1cxw

      @oe1cxw I learned Dirac delta as the limit of the sinc function as the main lobe's width -> 0; peak at 0 goes to infinity, all others -> 0.

      1 reply 0 retweets 1 like
    4. William D. Jones‏ @cr1901 11 May 2016
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      Replying to @cr1901

      @oe1cxw So I applied the same logic to Kronecker delta, thinking something similar applied, even though Idk if that's true.

      1 reply 0 retweets 0 likes
    5. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      Replying to @cr1901

      @cr1901 You still don't seem to understand. I'm not saying it has more than one (pointy) peak, I'm saying it has none!

      1 reply 0 retweets 0 likes
    6. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      Replying to @oe1cxw

      @cr1901 Look at the definition I gave: The Kronecker Delta is 1 ALONG A LINE, not on a point! What you are saying makes no sense.

      1 reply 0 retweets 0 likes
    7. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      Replying to @oe1cxw

      @cr1901 Because it does not matter how you derive it, you will always get something that does not change along the (1,1) direction.

      1 reply 0 retweets 0 likes
    8. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      Replying to @oe1cxw

      @cr1901 For example you can say kronecker(x,y) = dirac(x-y) and then use whatever definition of the dirac pulse you want.

      1 reply 0 retweets 0 likes
      Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 11 May 2016
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      @cr1901 The resulting kronecker(x,y) function will never have peaks at single points.

      9:44 AM - 11 May 2016
      1 reply 0 retweets 0 likes
        1. William D. Jones‏ @cr1901 11 May 2016
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          Replying to @oe1cxw

          @oe1cxw Turns out I misunderstood b/c Kronecker is in fact a function of two vars, not one (as I'm used to setting one of them constant).

          0 replies 0 retweets 1 like
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