I know what they mean, but the implication that FFT is anything else than a way to compute a DFT does hurt a lot!pic.twitter.com/5ReoIrIph8
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@cr1901 But then the FFT implementation is incomplete. FFT will produce the same values as DFT. No difference.
@cr1901 (except that FFT can only be done on dimensions that are powers of two of course)
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@oe1cxw I'll focus on R^n | n <= 2, please :P. Erm, I don't actually know how to convert the DFT magnitude to FFT XD. -
@cr1901 As I've said, that has nothing to do with DFT vs. FFT. You either scale forward _and_ reverse transform by 1/sqrt(n), or one by 1/n. - Show replies
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