I know what they mean, but the implication that FFT is anything else than a way to compute a DFT does hurt a lot!pic.twitter.com/5ReoIrIph8
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@oe1cxw I can't say I know what they mean (DFT will have different magnitude than FFT, but are compatible by a scale factor).
@cr1901 Many implementation factor out a scaling factor and leave it to the user to apply it. But you could do the same with the DFT algo.
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@cr1901 But then the FFT implementation is incomplete. FFT will produce the same values as DFT. No difference. -
@cr1901 (except that FFT can only be done on dimensions that are powers of two of course) - Show replies
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