Finally a clear understandable and readable version!
Finally wrote my own horrible version of this. https://twitter.com/ctrlshifti/status/1288745146759000064 …pic.twitter.com/jpsZEuhEh0
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Thanks. Twitter will use this to make your timeline better. UndoUndo
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Aw come on Claire! sprintf() it to a buffer then check if buf[strlen(buf)-1] is ‘0’, ‘2’, ‘4’, ‘6’, or ‘8’.
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Oh here’s another way that works on a 64 bit or fewer binary computer: int isEven(int n){ n *= n; n *= n; n *= n; n *= n; n *= n; n *= n; return n == 0; }
End of conversation
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you may need a big stack for negative numbers, but that's user error
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