GF(p) is a subfield of GF(p^n) and thus GF(p^n) is an n-dimensional vector space over GF(p) with the same addition and multiplication where multiplication is restricted to have one side in GF(p). (That's true in general for subfields.) So they're closely related. 1/2
Hmmm.. the description for GF2P8AFFINEQB states it is performing computations in the field GF(2^8). However, afaict in actuality it's performing computations in the vector space GF(2)^8, which is of course a very different algebraic structure. What am I missing?
-
-
-
Now if you have a multiplication with a constant in GF(p^n), that's a linear map. This is still true in the corresponding vector space, so it can be respresented by a matrix in GF(p)^n. The converse is not true, as linearity in GF(p)^n is a weaker condition than in GF(p^n).
- Show replies
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.