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oe1cxw's profile
Claire Xen 🏳️‍⚧️🏳️‍🌈🧙🏻‍♀️ BLM 🏴🚩
Claire Xen 🏳️‍⚧️🏳️‍🌈🧙🏻‍♀️ BLM 🏴🚩
Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩
@oe1cxw

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Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩

@oe1cxw

Neurodiverse trans geek girl. Yosys, RISC-V, SAT/SMT.

She/her/hers
clairexen.net
Joined September 2014

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    Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 15 Sep 2018
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    Hot take: The proper Verilog template for synchronously reset flip-flops looks like this. always @(posedge clk) begin [non-reset code here] if (reset) begin [reset code here] end end

    3:58 AM - 15 Sep 2018
    • 17 Retweets
    • 86 Likes
    • Will Green Mohamed Abdinur 𝕬𝖑𝖊𝖝𝖆𝖓𝖉𝖗𝖊 𝕯𝖚𝖒𝖔𝖓𝖙 Marsh Ray: #BLM Dimitri Stolnikov Dale hell writes memory initialization code for fun Javi Taiyou Hanssel Enrique M. N.
    13 replies 17 retweets 86 likes
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      2. Sachin Bhutada‏ @sachin_bhutada 15 Sep 2018
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        Replying to @oe1cxw

        always @(posedge clk) begin if (reset) begin [reset code here] end else begin [non-reset code here] end end seems more correct right? Both would synthesize identical

        1 reply 0 retweets 0 likes
      3. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 15 Sep 2018
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        Replying to @sachin_bhutada

        Only if you do assign reset values to *all* registers written to in [reset code]. If you have some registers in that block that do not have a reset value then your code will infer additional logic and they are not identical. That's the whole point.

        2 replies 0 retweets 5 likes
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      2. Phil Howard‏ @Gadgetoid 15 Sep 2018
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        Replying to @oe1cxw

        I use patterns like this in programming since it’s more explicit about scope and less needlessly verbose, ie: x = 1 if y > 5: x = 2 Rather than: if y > 5: x = 2 else: x = 1

        4 replies 0 retweets 3 likes
      3. Nicolas Cuervo‏ @primer_cuervo 15 Sep 2018
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        Replying to @Gadgetoid @oe1cxw

        When the 'if' condition es met then you have two 'write" operations with your preferred idiom, instead of one with the other. Wouldn't this escalate with larger code, making your option less optimal?

        2 replies 0 retweets 0 likes
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      2. Eric LaForest‏ @elaforest 15 Sep 2018
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        Replying to @oe1cxw

        Yes, and alternately: always @(posedge clock) begin [non-reset code] foo <= (reset == 1'b1) ? [reset value] : foo; bar <= (reset == 1'b1) ? [reset value] : bar; end Why? Compact, and simulates correctly if reset is X or Z. Else reset code fails to apply with an if.

        1 reply 0 retweets 4 likes
      3. Claire Xen  🏳️‍⚧️ 🏳️‍🌈 🧙🏻‍♀️ BLM  🏴 🚩‏ @oe1cxw 15 Sep 2018
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        Replying to @elaforest

        Your foo and bar are stuck at the reset value because non-blocking assignment. (All non-blocking assignment to foo/bar in [non-reset code] will be ignored and blocking assignments are not allowed because you must not mix blocking and non-blocking assignments for the same reg.)

        2 replies 0 retweets 2 likes
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      2. Zip CPU‏ @zipcpu 15 Sep 2018
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        Replying to @oe1cxw

        Didn't @OlofKindgren write a blog article about using resets in this fashion recently? I know I personally like to split my always blocks up and then use cascaded ifs to handle resets, but this is still a nice trick with a more general application.

        1 reply 0 retweets 8 likes
      3. Eric LaForest‏ @elaforest 15 Sep 2018
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        Replying to @zipcpu @oe1cxw @OlofKindgren

        Right here: https://olofkindgren.blogspot.com/2017/11/resetting-reset-handling.html … "Last assignment wins" is such a useful idiom.

        1 reply 0 retweets 6 likes
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      1. Nicolas Cuervo‏ @primer_cuervo 15 Sep 2018
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        Replying to @oe1cxw

        When I read this it made me think "why stating the obvious?", But the replies made me realize that it might not be as obvious as I thought it was (which is rather concerning :/ )

        0 replies 0 retweets 0 likes
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      1. Phill Ferguson‏ @Phill_Ferg 15 Sep 2018
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        Replying to @oe1cxw

        I think this thread highlights the distinct difference between coding for behaviour and describing a hardware function . All of the above is just a mux (or lut) so the concept of write doesnt make sense if you realise how it will be implemented.

        0 replies 0 retweets 1 like
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