1/ Short proof that complex normal matrics (A A* = A* A) are diagonalizable
3/ Work in a basis including the eigenvector as first element, so first column of A is zero, except in top-left corner
-
-
Is it obvious that the normal property is basis-independent?
-
Pretty obvious: AA* = A*A invariant under unitary conjugation of A
- 1 more reply
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.