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michael_nielsen's profile
michael_nielsen
michael_nielsen
michael_nielsen
@michael_nielsen

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michael_nielsen

@michael_nielsen

Searching for the numinous. Co-purveyor of https://quantum.country/ 

San Francisco, CA
michaelnielsen.org
Joined July 2008

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    1. Grant Sanderson‏ @3blue1brown Feb 21
      • Report Tweet

      Which of these do you want to learn more about: - What e^A means when A is a matrix - How to think about solutions to linear systems of ordinary differential equations.

      108 replies 41 retweets 269 likes
    2. michael_nielsen‏ @michael_nielsen Feb 21
      • Report Tweet
      Replying to @3blue1brown

      I'm sure you've seen this (and maybe we've talked about it?), but just in case not, it's a very good paper with one of the best titles ever: "19 dubious ways to exponentiate a matrix" http://www.cs.cornell.edu/cv/researchpdf/19ways+.pdf …

      4 replies 10 retweets 93 likes
    3. Grant Sanderson‏ @3blue1brown Feb 21
      • Report Tweet
      Replying to @michael_nielsen

      I had not seen this, I'll check it out now!

      1 reply 0 retweets 6 likes
    4. michael_nielsen‏ @michael_nielsen Feb 21
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      Replying to @3blue1brown

      It's a really fun exercise in realizing how many ways there are to think about a mathematical object!

      2 replies 0 retweets 11 likes
    5. michael_nielsen‏ @michael_nielsen Feb 21
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      Replying to @michael_nielsen @3blue1brown

      A beautiful little result about exponentiation that should be much better known is this result of Thompson's; it says exponentiation of Hermitian matrices almost commutes.pic.twitter.com/LotR9av0cf

      3 replies 11 retweets 51 likes
    6. Grant Sanderson‏ @3blue1brown Feb 21
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      Replying to @michael_nielsen

      Rather than framing this as something which should be better known, might it be better to say the spectral theorem and its implications should be deeper in peoples bones?

      2 replies 0 retweets 3 likes
    7. michael_nielsen‏ @michael_nielsen Feb 21
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      Replying to @3blue1brown

      Ofc I love the spectral theorem - it's coincidentally the result I've proven most often in public writing - but this result of Thompson's is very different (and seems to be much harder).

      1 reply 0 retweets 3 likes
    8. Grant Sanderson‏ @3blue1brown Feb 21
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      Replying to @michael_nielsen

      Hmm, okay, I'm clearly taking too quick a glace then. Just to check myself, am I right in thinking U and V are the change of basis matrices which diagonalize H and K? So e^(iUHU*) will be diagonal with e^{i lambda} entries on the diagonal?

      2 replies 1 retweet 2 likes
    9. Grant Sanderson‏ @3blue1brown Feb 21
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      Replying to @3blue1brown @michael_nielsen

      Hmm, I guess not, actually. If that were the case, UHU* + VKV* would be diagonal, with eigenvalues lambda_i + mu_i, if lambda_i are the eigenvalues of H and mu_i are the eigenvalues of K. So the rhs above should be diagonal with e^{i(lambda_i + mu_i)} entries on the diagonal.

      2 replies 1 retweet 3 likes
      michael_nielsen‏ @michael_nielsen Feb 21
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      Replying to @3blue1brown

      That's right. When H and K don't share a common basis there's no obvious reason to expect there to be any relationship between the spectrum of exp(iH) exp(iK) and H and K. Thompson tells you there's a really strong relationship.

      12:39 PM - 21 Feb 2019
      • 1 Retweet
      • 3 Likes
      • Warren Moore Igor Carron Ilya Arbabi
      1 reply 1 retweet 3 likes
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        2. Grant Sanderson‏ @3blue1brown Feb 21
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          Replying to @michael_nielsen

          Interesting. Is there a short answer to what U and V are in this case?

          1 reply 1 retweet 2 likes
        3. michael_nielsen‏ @michael_nielsen Feb 21
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          Replying to @3blue1brown

          Not as far as I know. In fact, I'm not even certain there's a constructive proof known - unless the situation has changed, Thompson's result depends on the proof of Horn's Conjecture by Allen Knutson, Terry Tao, and Alexander Klyachko, and I've never mastered that.

          2 replies 1 retweet 2 likes
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