Which of these do you want to learn more about: - What e^A means when A is a matrix - How to think about solutions to linear systems of ordinary differential equations.
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Replying to @3blue1brown
I'm sure you've seen this (and maybe we've talked about it?), but just in case not, it's a very good paper with one of the best titles ever: "19 dubious ways to exponentiate a matrix" http://www.cs.cornell.edu/cv/researchpdf/19ways+.pdf …
4 replies 10 retweets 93 likes -
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Replying to @3blue1brown
It's a really fun exercise in realizing how many ways there are to think about a mathematical object!
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Replying to @michael_nielsen @3blue1brown
A beautiful little result about exponentiation that should be much better known is this result of Thompson's; it says exponentiation of Hermitian matrices almost commutes.pic.twitter.com/LotR9av0cf
3 replies 11 retweets 51 likes -
Replying to @michael_nielsen
Rather than framing this as something which should be better known, might it be better to say the spectral theorem and its implications should be deeper in peoples bones?
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Replying to @3blue1brown
Ofc I love the spectral theorem - it's coincidentally the result I've proven most often in public writing - but this result of Thompson's is very different (and seems to be much harder).
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Replying to @michael_nielsen
Hmm, okay, I'm clearly taking too quick a glace then. Just to check myself, am I right in thinking U and V are the change of basis matrices which diagonalize H and K? So e^(iUHU*) will be diagonal with e^{i lambda} entries on the diagonal?
2 replies 1 retweet 2 likes
No, that's not what's going on at all. Hmm. When H and K don't commute the product exp(iH) exp(iK) could be... well, very complicated!
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