EE followers: do you have a good idea why an UART would behave like that? i.e. sharp edges but slow rolloff from rising to falling edge. please only reply if you're certain, i'm more than capable of guessing myselfpic.twitter.com/kuCqONlq66
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EE followers: do you have a good idea why an UART would behave like that? i.e. sharp edges but slow rolloff from rising to falling edge. please only reply if you're certain, i'm more than capable of guessing myselfpic.twitter.com/kuCqONlq66
my current best guess is that the rolloff happens because it turns off high side drivers while idle and relies on pull resistors to maintain the level; but it's still a CMOS output because it has fast rising/falling edges not sure why though, lower static power?
you can see it in the waveform but I should mention it explicitly too: this is -supposed- to be a completely ordinary 3.3 V TTL UART, it does -not- have a charge pump anywhere, or at least isn't supposed to. this is -not- RS-232
whitequark Retweeted Muzaffer Kal @ 🏡 🇺🇸
the best hypothesis so far is that the chip designers went for a multidrop UART that would only exhibit a bus conflict for a very short time, though I couldn't find any explicit mention of anything like that feature, or even any mention of half-duplexhttps://twitter.com/DSPonFPGA/status/1264739607180005378 …
whitequark added,
thank you! brilliant find. I thought of looking at similar CPUs but missed this one
Isn't that for the synchronous serial controller though, not the UART? I don't see anything there related to this kind of feature for the UART.
This kind of drive is used in smart cards readers. The IO line of a smart card is open drain but for high data rates like f/d= 16 or 8, a pullup is not enough, so iso7816 drivers go push pull for a short time before letting it open drain. If not implemented right, can be a mess.
Consistent with the fact that the doc shows a bidir IO line.
TxD2 is not bidir though, but it is listed as hi-z during reset and the like, so clearly the "bidir" marking in the doc doesn't have much relevance to whether the driver has a high-z mode or not. TxD1 is bidir because it is shared with a GPIO.
Oh, missed that detail. Anyway yeah, it would have it due to the reset behavior either way. I wonder why the UART behaves like that though.
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