@khanacademy 6/pi
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@khanacademy X intercept of the curve is Pi. Area under curve found by taking the definite integral of f(x) from 0 to Pi. A=6. h=6/piThanks. Twitter will use this to make your timeline better. UndoUndo
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@khanacademy I'm stumped for how to approach this. Would you start off by finding the area, then the x length, then the h height? -
@Zantareous@khanacademy it says the area of the rectangle is the are of f(x) to x=0 so you have to integrate from x=0 to x=Pi f(x)
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@khanacademy pi/Zeta(2)Thanks. Twitter will use this to make your timeline better. UndoUndo
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@khanacademy 6/pi. Definite integral of fx from 0 to pi gives the area covered by it which is A=6. Length of rect=pi. Height=A/L = 6/piThanks. Twitter will use this to make your timeline better. UndoUndo
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@khanacademy I'm sorry, I thought in a sinewave then in the máximum peak then in the real value, the Root Medium Square RMS, that is 0.7071Thanks. Twitter will use this to make your timeline better. UndoUndo
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