f(f(x)) = x² - x + 1
f(0) = ?
(@edsaperia inflicted this on me earlier :P )
Why do you believe that a fixed point of f(f(x)) be a fixed point of f(x)? ( let g(x) = -x for instance. Then g(g(1))=1, but g(1)=-1 )
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Yeah I think I had that logic backwards, fixed points propagate the other way.
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Anyhow I went for a walk and realized f(x) = -x + 1 so f(0)=1 Dunno why it took so long to think of -x, ws stuck on x+? for a whl
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