f(f(x)) = x² - x + 1
f(0) = ?
(@edsaperia inflicted this on me earlier :P )
-
-
because + 1 is the only output that doesn't depend on x, so I assume that applying f once does + 1/2
-
Take a simplified version of the problem (equivalent in your analysis :P ) g(g(x))=1 . defining g(x)=1 is a solution to this, giving g(0)=1
End of conversation
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.