if f(0) = 1, then what is f(x)
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f(x) is a function such that f(f(x)) = x² - x + 1
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1/2?
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After giving this damned problem a long-ish thought, I found that f(0) = 1.
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I keep getting to 1, but I probably suck at math now.
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You're claiming f(0) can be any real number?
Thanks. Twitter will use this to make your timeline better. UndoUndo
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I got as far as f(1)=1, because I believe any fixed point on f(f(x)) must also be a fixed point of f(x)...
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Why do you believe that a fixed point of f(f(x)) be a fixed point of f(x)? ( let g(x) = -x for instance. Then g(g(1))=1, but g(1)=-1 )
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