@graveolens What sort of function is acceptable? f(x)=1 for x<=1, f(x)=0 for x>1 works, but it seems that's not what you want.
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@tshellstudio f(x)=exp(-4x) appears to work. - 6 more replies
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@graveolens f(x)=exp(-4x) satisfies, it would seem, not sure if there are any others.Thanks. Twitter will use this to make your timeline better. UndoUndo
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@graveolens Any function which is uniformly 1 across some range(s) and has integral 1, e.g., f(x) = { 1 if 1 <= x <= 2; 0 otherwise } -
@markgritter I tend to think in analytic terms so I look for functions defined by series not piecewise continuous (I admit a bias for them)
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@graveolens the Dirac Delta function?Thanks. Twitter will use this to make your timeline better. UndoUndo
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