r = exp(2*pi*j/3.0) def g(z): s = 1.0 for u in range(1,150): S=sin((s/z)^r) A=sin((z/S)^(r^2)) s=sin(A/z) ret s/|s|pic.twitter.com/H4gjAtlvTj
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@graveolens sorry for the broken python, I just wanted to get the whole algorithm in the space of a tweet.