5 = 5
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4096 = 4^6 + (9*0)
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Had a nice chat about these Friedman numbers (and the *nice* version) here.https://twitter.com/panlepan/status/922737702012891137 …
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Conjecture : For all integer a>1(not a power of 10), there exists M such that n>M => a^n is a Friedman number.
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Can you do 121 = 11^2?
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128 = 2^(8-1)
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3375 = (3+7+5)^3
Thanks. Twitter will use this to make your timeline better. UndoUndo
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5832 = ((2*5)+8)^3
Thanks. Twitter will use this to make your timeline better. UndoUndo
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Do they need to be in order?
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