Doesn't this establish that if it converges, it converges to 2? What about establishing that it converges?
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correct. as presented the above is as valid as the following "proof"pic.twitter.com/rD1SGtCKCt
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If it really converges then please see the attached photos An important one…pic.twitter.com/QCPXnMD4aA
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Thanks to http://fb.com/james.ross.7374 for reliasing of my mistake.I accept it that(∞)symbol in third & fourth line is wrong otherwise it's right
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Is this at all useful to know or is it, as my electrical engineering lecturer once said: "Mathematics is nothing but mental self-abuse"
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Numerical algorithm is straight-forward x[1]:=sqrt(2); for i:=2 to n do x[i]:=sqrt(2+x[i-1]) In a nutshell: successor: = sqrt(2+predecessor)
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You still have to prove that it converges.
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alguien le estan gustando las matematicas.
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Jaja si, les estoy entendiendo
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I got a stack error on my calculator trying to test this :P
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