"... that is equal to the sum of its PROPER positive divisors, that is, the sum of its positive divisors excluding the number itself"
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496=1+2+4+8+16+31+62+124+248,
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33550336=1+2+4+8+16+32+64+128+256+512+1024+2048+4096+8191+16382+32764+65528+131056+262112+524224+1048448+2096896+4193792+8387584+16775168
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As always in maths...
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Euclid-Euler Theorem
http://mathworld.wolfram.com/PerfectNumber.html …
6 28 496 8128 33550336 8589869056 137438691328 2305843008139952128Thanks. Twitter will use this to make your timeline better. UndoUndo
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Euclid assumed and Euler proved that if p is prime & 2ᴾ-1 is Mersenne prime, then 2ᴾ⁻¹(2ᴾ-1) is an even perfect number.
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No. Euclid proved that statement and Euler proved the converse.
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It's supposed to be a sum of proper divisors, not normal divisors.
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No, because 1 isn't proper either
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Divisors of 6 are 1,2,3,6. Factors are 2 and 3, but not 1
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