4lunes = square + 4semicircles - big circle = square + 2small circles - big circle Big circle radius : small circle radius = √2:1 => qed
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@Phootie for you and my dear young EmmaThanks. Twitter will use this to make your timeline better. UndoUndo
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This can be generalised with any right triangle, i.e. half a rectangle. Pythag is the key.
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Circle area is ¶r², so it does give 2¶ area, just not obvious.
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Ah fuck I missed my r^2
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Sharp guy, that Hippocrates.
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Hmm, correct but not the fundamental proof? Step 2, basis for two small hemispheres equal one big hemisphere on the hypotenuse?
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