X=2, Y=2
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I used know all this stuff, don't depress me.
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It's easier to solve the equation by rewriting it as (x-1)(y-1)=1.
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The solutions are (0,0) and all the points of the curve 1/(1-1/x)

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pretty sure it's still sum of the squares of smaller sides equal to the product of the squares of the smaller sides for x=sec (theta), y=csc (theta)
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Except that x = sec^2(theta), Y=csc^2(theta).

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x+y=xy x-xy=-y x(1-y)=-y x=(1-y)/y Easy pizzy
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Incorrect. What happens when y=1?
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