1¹ = 1 contains exactly 1 embedded 1
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1¹ should contain two ones to be like 11¹¹
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21²¹ = 5842587018385982521381124421 contains exactly two embedded twenty-ones 25²⁵ = 88817841970012523233890533447265625 contains exactly two embedded twenty-fives
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>>> for i in range(100): ...: if str(i**i).count(str(i)) == 2: ...: print(i) ...: ...: 11 16 19 21 25 31 32 33 52 53 61 66 75 77 79 83 95 96
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I want to see this with i**i.count(str(i)) >= 2) but tis early and bed is still warm
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Today is 73rd day of year 2020. 2⁷³ is the largest prime power of 2 which doesn't contain 1
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2^73 is divisible by 2
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Any n^n containing n embedded n's?
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No, here a counterexample -> 2^2=4
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